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6x^2+6x-1=-5x-4
We move all terms to the left:
6x^2+6x-1-(-5x-4)=0
We get rid of parentheses
6x^2+6x+5x+4-1=0
We add all the numbers together, and all the variables
6x^2+11x+3=0
a = 6; b = 11; c = +3;
Δ = b2-4ac
Δ = 112-4·6·3
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-7}{2*6}=\frac{-18}{12} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+7}{2*6}=\frac{-4}{12} =-1/3 $
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